Base | Representation |
---|---|
bin | 11110000100000011100101… |
… | …011110110101100111010010 |
3 | 122100011010020201200201010121 |
4 | 132010003211132311213102 |
5 | 114312243303031301300 |
6 | 1145113030333220454 |
7 | 36564405625352464 |
oct | 3604034536654722 |
9 | 570133221621117 |
10 | 132220123306450 |
11 | 3914726a6a9193 |
12 | 129b518b93172a |
13 | 58a13c522723a |
14 | 24916b9552134 |
15 | 10445374c181a |
hex | 7840e57b59d2 |
132220123306450 has 96 divisors (see below), whose sum is σ = 255448002281472. Its totient is φ = 50863157928000.
The previous prime is 132220123306423. The next prime is 132220123306451. The reversal of 132220123306450 is 54603321022231.
It is a super-2 number, since 2×1322201233064502 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (132220123306451) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 197031189 + ... + 197701111.
It is an arithmetic number, because the mean of its divisors is an integer number (2660916690432).
Almost surely, 2132220123306450 is an apocalyptic number.
132220123306450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132220123306450 is a deficient number, since it is larger than the sum of its proper divisors (123227878975022).
132220123306450 is a wasteful number, since it uses less digits than its factorization.
132220123306450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 670760 (or 670755 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 132220123306450 its reverse (54603321022231), we get a palindrome (186823444328681).
The spelling of 132220123306450 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred twenty-three million, three hundred six thousand, four hundred fifty".
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