Base | Representation |
---|---|
bin | 11110000100000011100111… |
… | …000101111001001111111011 |
3 | 122100011010022121112020201212 |
4 | 132010003213011321033323 |
5 | 114312243331440302141 |
6 | 1145113033140233335 |
7 | 36564406404111512 |
oct | 3604034705711773 |
9 | 570133277466655 |
10 | 132220150322171 |
11 | 3914728398052a |
12 | 129b519899b84b |
13 | 58a13ca9c5a82 |
14 | 24916bcd85679 |
15 | 1044539a5b2eb |
hex | 7840e71793fb |
132220150322171 has 2 divisors, whose sum is σ = 132220150322172. Its totient is φ = 132220150322170.
The previous prime is 132220150322089. The next prime is 132220150322269. The reversal of 132220150322171 is 171223051022231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132220150322171 - 242 = 127822103811067 is a prime.
It is not a weakly prime, because it can be changed into another prime (132220150342171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66110075161085 + 66110075161086.
It is an arithmetic number, because the mean of its divisors is an integer number (66110075161086).
Almost surely, 2132220150322171 is an apocalyptic number.
132220150322171 is a deficient number, since it is larger than the sum of its proper divisors (1).
132220150322171 is an equidigital number, since it uses as much as digits as its factorization.
132220150322171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
The spelling of 132220150322171 in words is "one hundred thirty-two trillion, two hundred twenty billion, one hundred fifty million, three hundred twenty-two thousand, one hundred seventy-one".
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