Base | Representation |
---|---|
bin | 11110000100000011110000… |
… | …111010010000110010001011 |
3 | 122100011010202002111000222111 |
4 | 132010003300322100302023 |
5 | 114312244201122420003 |
6 | 1145113101343003151 |
7 | 36564413444201143 |
oct | 3604036072206213 |
9 | 570133662430874 |
10 | 132220315045003 |
11 | 391473589591a9 |
12 | 129b5223b994b7 |
13 | 58a1425b7b0c3 |
14 | 24916d6bc3923 |
15 | 1044549247e6d |
hex | 7840f0e90c8b |
132220315045003 has 4 divisors (see below), whose sum is σ = 139179278994760. Its totient is φ = 125261351095248.
The previous prime is 132220315045001. The next prime is 132220315045043. The reversal of 132220315045003 is 300540513022231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132220315045003 - 21 = 132220315045001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132220315045001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3479481974850 + ... + 3479481974887.
It is an arithmetic number, because the mean of its divisors is an integer number (34794819748690).
Almost surely, 2132220315045003 is an apocalyptic number.
132220315045003 is a deficient number, since it is larger than the sum of its proper divisors (6958963949757).
132220315045003 is an equidigital number, since it uses as much as digits as its factorization.
132220315045003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6958963949756.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 132220315045003 its reverse (300540513022231), we get a palindrome (432760828067234).
The spelling of 132220315045003 in words is "one hundred thirty-two trillion, two hundred twenty billion, three hundred fifteen million, forty-five thousand, three".
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