Search a number
-
+
13222033113 = 34407344371
BaseRepresentation
bin11000101000001100…
…00011011011011001
31021010110120212122010
430110012003123121
5204034320024423
610024002020133
7645440266332
oct142406033331
937113525563
1013222033113
1156755471a3
122690047649
1313293a1943
148d6045289
15525bae693
hex3141836d9

13222033113 has 4 divisors (see below), whose sum is σ = 17629377488. Its totient is φ = 8814688740.

The previous prime is 13222033109. The next prime is 13222033171. The reversal of 13222033113 is 31133022231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13222033113 - 22 = 13222033109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13222033113.

It is not an unprimeable number, because it can be changed into a prime (13222033183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2203672183 + ... + 2203672188.

It is an arithmetic number, because the mean of its divisors is an integer number (4407344372).

Almost surely, 213222033113 is an apocalyptic number.

It is an amenable number.

13222033113 is a deficient number, since it is larger than the sum of its proper divisors (4407344375).

13222033113 is an equidigital number, since it uses as much as digits as its factorization.

13222033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4407344374.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 13222033113 its reverse (31133022231), we get a palindrome (44355055344).

The spelling of 13222033113 in words is "thirteen billion, two hundred twenty-two million, thirty-three thousand, one hundred thirteen".

Divisors: 1 3 4407344371 13222033113