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132220466115531 = 344073488705177
BaseRepresentation
bin11110000100000011111001…
…111010100011001111001011
3122100011011010121202012210020
4132010003321322203033023
5114312300003311144111
61145113124340551523
736564420260240043
oct3604037172431713
9570134117665706
10132220466115531
1139147426161782
12129b52666b25a3
1358a144b263351
14249170ccaa723
151044557639906
hex7840f9ea33cb

132220466115531 has 4 divisors (see below), whose sum is σ = 176293954820712. Its totient is φ = 88146977410352.

The previous prime is 132220466115481. The next prime is 132220466115583. The reversal of 132220466115531 is 135511664022231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132220466115531 - 217 = 132220465984459 is a prime.

It is a super-3 number, since 3×1322204661155313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (132220466114531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22036744352586 + ... + 22036744352591.

It is an arithmetic number, because the mean of its divisors is an integer number (44073488705178).

Almost surely, 2132220466115531 is an apocalyptic number.

132220466115531 is a deficient number, since it is larger than the sum of its proper divisors (44073488705181).

132220466115531 is an equidigital number, since it uses as much as digits as its factorization.

132220466115531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44073488705180.

The product of its (nonzero) digits is 259200, while the sum is 42.

The spelling of 132220466115531 in words is "one hundred thirty-two trillion, two hundred twenty billion, four hundred sixty-six million, one hundred fifteen thousand, five hundred thirty-one".

Divisors: 1 3 44073488705177 132220466115531