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13222111021057 is a prime number
BaseRepresentation
bin1100000001101000001100…
…1110110000100000000001
31201211000120122120110111201
43000122003032300200001
53213112340410133212
644042053130341201
72533160144210551
oct300320316604001
951730518513451
1013222111021057
114238513a76314
12159664a28a801
1374babbb2b5b3
14339d4c907161
1517de0dd69b57
hexc06833b0801

13222111021057 has 2 divisors, whose sum is σ = 13222111021058. Its totient is φ = 13222111021056.

The previous prime is 13222111020983. The next prime is 13222111021169. The reversal of 13222111021057 is 75012011122231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11518122794896 + 1703988226161 = 3393836^2 + 1305369^2 .

It is an emirp because it is prime and its reverse (75012011122231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13222111021057 is a prime.

It is not a weakly prime, because it can be changed into another prime (13222111028057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611055510528 + 6611055510529.

It is an arithmetic number, because the mean of its divisors is an integer number (6611055510529).

Almost surely, 213222111021057 is an apocalyptic number.

It is an amenable number.

13222111021057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13222111021057 is an equidigital number, since it uses as much as digits as its factorization.

13222111021057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 28.

Adding to 13222111021057 its reverse (75012011122231), we get a palindrome (88234122143288).

The spelling of 13222111021057 in words is "thirteen trillion, two hundred twenty-two billion, one hundred eleven million, twenty-one thousand, fifty-seven".