Base | Representation |
---|---|
bin | 10011001111011011001… |
… | …011001110001111110010 |
3 | 11200101220121222202122221 |
4 | 103033123023032033302 |
5 | 133130412410041424 |
6 | 2451231450551254 |
7 | 164346100340644 |
oct | 23173313161762 |
9 | 4611817882587 |
10 | 1322232112114 |
11 | 46a834614071 |
12 | 194310a3852a |
13 | 978bc067b74 |
14 | 47dd40aa894 |
15 | 245dab029e4 |
hex | 133db2ce3f2 |
1322232112114 has 4 divisors (see below), whose sum is σ = 1983348168174. Its totient is φ = 661116056056.
The previous prime is 1322232112109. The next prime is 1322232112141. The reversal of 1322232112114 is 4112112322231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1278516411225 + 43715700889 = 1130715^2 + 209083^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330558028027 + ... + 330558028030.
Almost surely, 21322232112114 is an apocalyptic number.
1322232112114 is a deficient number, since it is larger than the sum of its proper divisors (661116056060).
1322232112114 is an equidigital number, since it uses as much as digits as its factorization.
1322232112114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 661116056059.
The product of its digits is 1152, while the sum is 25.
Adding to 1322232112114 its reverse (4112112322231), we get a palindrome (5434344434345).
The spelling of 1322232112114 in words is "one trillion, three hundred twenty-two billion, two hundred thirty-two million, one hundred twelve thousand, one hundred fourteen".
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