Base | Representation |
---|---|
bin | 111101100100100011… |
… | …1100100010101001001 |
3 | 110122021212022200101121 |
4 | 1323021013210111021 |
5 | 4131243121114423 |
6 | 140424214315241 |
7 | 12360420565252 |
oct | 1731107442511 |
9 | 418255280347 |
10 | 132223223113 |
11 | 51091620603 |
12 | 21761358b21 |
13 | c612677677 |
14 | 658486db29 |
15 | 368d11b45d |
hex | 1ec91e4549 |
132223223113 has 4 divisors (see below), whose sum is σ = 132230125008. Its totient is φ = 132216321220.
The previous prime is 132223223089. The next prime is 132223223129. The reversal of 132223223113 is 311322322231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132223223113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132223223173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3422131 + ... + 3460552.
It is an arithmetic number, because the mean of its divisors is an integer number (33057531252).
Almost surely, 2132223223113 is an apocalyptic number.
It is an amenable number.
132223223113 is a deficient number, since it is larger than the sum of its proper divisors (6901895).
132223223113 is an equidigital number, since it uses as much as digits as its factorization.
132223223113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6901894.
The product of its digits is 2592, while the sum is 25.
Adding to 132223223113 its reverse (311322322231), we get a palindrome (443545545344).
The spelling of 132223223113 in words is "one hundred thirty-two billion, two hundred twenty-three million, two hundred twenty-three thousand, one hundred thirteen".
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