Base | Representation |
---|---|
bin | 11000101000001111… |
… | …00001111010011001 |
3 | 1021010111022112111202 |
4 | 30110013201322121 |
5 | 204034414420441 |
6 | 10024014203545 |
7 | 645443500541 |
oct | 142407417231 |
9 | 37114275452 |
10 | 13222420121 |
11 | 5675790a39 |
12 | 26901b35b5 |
13 | 13294a8b41 |
14 | 8d6106321 |
15 | 525c3919b |
hex | 3141e1e99 |
13222420121 has 2 divisors, whose sum is σ = 13222420122. Its totient is φ = 13222420120.
The previous prime is 13222420087. The next prime is 13222420147. The reversal of 13222420121 is 12102422231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12586371721 + 636048400 = 112189^2 + 25220^2 .
It is an emirp because it is prime and its reverse (12102422231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13222420121 - 210 = 13222419097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13222420093 and 13222420102.
It is not a weakly prime, because it can be changed into another prime (13222423121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611210060 + 6611210061.
It is an arithmetic number, because the mean of its divisors is an integer number (6611210061).
Almost surely, 213222420121 is an apocalyptic number.
It is an amenable number.
13222420121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222420121 is an equidigital number, since it uses as much as digits as its factorization.
13222420121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 13222420121 its reverse (12102422231), we get a palindrome (25324842352).
The spelling of 13222420121 in words is "thirteen billion, two hundred twenty-two million, four hundred twenty thousand, one hundred twenty-one".
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