Base | Representation |
---|---|
bin | 10011001111011111010… |
… | …111111001000101001001 |
3 | 11200102002112111222111220 |
4 | 103033133113321011021 |
5 | 133131033422322103 |
6 | 2451242444312253 |
7 | 164350614105225 |
oct | 23173727710511 |
9 | 4612075458456 |
10 | 1322302542153 |
11 | 46a87034920a |
12 | 194330542689 |
13 | 97900827348 |
14 | 47ddd5a1785 |
15 | 245e1db5c53 |
hex | 133df5f9149 |
1322302542153 has 4 divisors (see below), whose sum is σ = 1763070056208. Its totient is φ = 881535028100.
The previous prime is 1322302542149. The next prime is 1322302542163. The reversal of 1322302542153 is 3512452032231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1322302542153 - 22 = 1322302542149 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1322302542133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220383757023 + ... + 220383757028.
It is an arithmetic number, because the mean of its divisors is an integer number (440767514052).
Almost surely, 21322302542153 is an apocalyptic number.
It is an amenable number.
1322302542153 is a deficient number, since it is larger than the sum of its proper divisors (440767514055).
1322302542153 is an equidigital number, since it uses as much as digits as its factorization.
1322302542153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 440767514054.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 1322302542153 its reverse (3512452032231), we get a palindrome (4834754574384).
The spelling of 1322302542153 in words is "one trillion, three hundred twenty-two billion, three hundred two million, five hundred forty-two thousand, one hundred fifty-three".
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