13223110554113 has 4 divisors (see below), whose sum is σ = 13223888996400. Its totient is φ = 13222332111828.

The previous prime is 13223110554097. The next prime is 13223110554131. The reversal of 13223110554113 is 31145501132231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13223110554113 - 2⁴ = 13223110554097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13223110554113.

It is not an unprimeable number, because it can be changed into a prime (13223110554413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389195663 + ... + 389229636.

It is an arithmetic number, because the mean of its divisors is an integer number (3305972249100).

Almost surely, 2^{13223110554113} is an apocalyptic number.

It is an amenable number.

13223110554113 is a deficient number, since it is larger than the sum of its proper divisors (778442287).

13223110554113 is an equidigital number, since it uses as much as digits as its factorization.

13223110554113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 778442286.

The product of its (nonzero) digits is 10800, while the sum is 32.

Adding to 13223110554113 its reverse (31145501132231), we get a palindrome (44368611686344).

The spelling of 13223110554113 in words is "thirteen trillion, two hundred twenty-three billion, one hundred ten million, five hundred fifty-four thousand, one hundred thirteen".