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132231314753 = 599220753447
BaseRepresentation
bin111101100100110011…
…0011011110101000001
3110122022102112210000222
41323021212123311001
54131302204033003
6140425103552425
712360546426116
oct1731146336501
9418272483028
10132231314753
1151096147a0a
1221763bbb715
13c61424b715
14658597890d
15368dbb8c38
hex1ec999bd41

132231314753 has 4 divisors (see below), whose sum is σ = 132452068800. Its totient is φ = 132010560708.

The previous prime is 132231314749. The next prime is 132231314767. The reversal of 132231314753 is 357413132231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132231314753 - 22 = 132231314749 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132231314723) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110376125 + ... + 110377322.

It is an arithmetic number, because the mean of its divisors is an integer number (33113017200).

Almost surely, 2132231314753 is an apocalyptic number.

It is an amenable number.

132231314753 is a deficient number, since it is larger than the sum of its proper divisors (220754047).

132231314753 is an equidigital number, since it uses as much as digits as its factorization.

132231314753 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 220754046.

The product of its digits is 45360, while the sum is 35.

Adding to 132231314753 its reverse (357413132231), we get a palindrome (489644446984).

The spelling of 132231314753 in words is "one hundred thirty-two billion, two hundred thirty-one million, three hundred fourteen thousand, seven hundred fifty-three".

Divisors: 1 599 220753447 132231314753