Base | Representation |
---|---|
bin | 11110000100001110110101… |
… | …011000000101010001101001 |
3 | 122100012021102110020202211222 |
4 | 132010032311120011101221 |
5 | 114312443021442143423 |
6 | 1145122345023031425 |
7 | 36565314133232336 |
oct | 3604166530052151 |
9 | 570167373222758 |
10 | 132232201131113 |
11 | 391513a8285666 |
12 | 129b75a073b575 |
13 | 58a259b539c55 |
14 | 249210362b98d |
15 | 10449e29b63c8 |
hex | 7843b5605469 |
132232201131113 has 2 divisors, whose sum is σ = 132232201131114. Its totient is φ = 132232201131112.
The previous prime is 132232201131103. The next prime is 132232201131143. The reversal of 132232201131113 is 311131102232231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 85088762063449 + 47143439067664 = 9224357^2 + 6866108^2 .
It is a cyclic number.
It is not a de Polignac number, because 132232201131113 - 210 = 132232201130089 is a prime.
It is not a weakly prime, because it can be changed into another prime (132232201131103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66116100565556 + 66116100565557.
It is an arithmetic number, because the mean of its divisors is an integer number (66116100565557).
Almost surely, 2132232201131113 is an apocalyptic number.
It is an amenable number.
132232201131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
132232201131113 is an equidigital number, since it uses as much as digits as its factorization.
132232201131113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 132232201131113 its reverse (311131102232231), we get a palindrome (443363303363344).
The spelling of 132232201131113 in words is "one hundred thirty-two trillion, two hundred thirty-two billion, two hundred one million, one hundred thirty-one thousand, one hundred thirteen".
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