Base | Representation |
---|---|
bin | 10011001111100000100… |
… | …110010100000111010001 |
3 | 11200102010222012102201211 |
4 | 103033200212110013101 |
5 | 133131104203200423 |
6 | 2451244501100121 |
7 | 164351253620041 |
oct | 23174046240721 |
9 | 4612128172654 |
10 | 1322323100113 |
11 | 46a880a0a764 |
12 | 1943373b7641 |
13 | 97904b74712 |
14 | 480021d3721 |
15 | 245e3ac710d |
hex | 133e09941d1 |
1322323100113 has 2 divisors, whose sum is σ = 1322323100114. Its totient is φ = 1322323100112.
The previous prime is 1322323100099. The next prime is 1322323100233. The reversal of 1322323100113 is 3110013232231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1068178059729 + 254145040384 = 1033527^2 + 504128^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1322323100113 is a prime.
It is a super-2 number, since 2×13223231001132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1322323140113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661161550056 + 661161550057.
It is an arithmetic number, because the mean of its divisors is an integer number (661161550057).
Almost surely, 21322323100113 is an apocalyptic number.
It is an amenable number.
1322323100113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322323100113 is an equidigital number, since it uses as much as digits as its factorization.
1322323100113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1322323100113 its reverse (3110013232231), we get a palindrome (4432336332344).
The spelling of 1322323100113 in words is "one trillion, three hundred twenty-two billion, three hundred twenty-three million, one hundred thousand, one hundred thirteen".
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