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1322350134041 is a prime number
BaseRepresentation
bin10011001111100010001…
…101011100001100011001
311200102012212001220022102
4103033202031130030121
5133131133113242131
62451251304333145
7164352032453126
oct23174215341431
94612185056272
101322350134041
1146a8951a4752
121943444741b5
139790a64b621
1448005a2d74d
15245e61671cb
hex133e235c319

1322350134041 has 2 divisors, whose sum is σ = 1322350134042. Its totient is φ = 1322350134040.

The previous prime is 1322350134023. The next prime is 1322350134191. The reversal of 1322350134041 is 1404310532231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 721104974041 + 601245160000 = 849179^2 + 775400^2 .

It is an emirp because it is prime and its reverse (1404310532231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1322350134041 - 226 = 1322283025177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1322350133995 and 1322350134013.

It is not a weakly prime, because it can be changed into another prime (1322350134241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661175067020 + 661175067021.

It is an arithmetic number, because the mean of its divisors is an integer number (661175067021).

Almost surely, 21322350134041 is an apocalyptic number.

It is an amenable number.

1322350134041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322350134041 is an equidigital number, since it uses as much as digits as its factorization.

1322350134041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1322350134041 its reverse (1404310532231), we get a palindrome (2726660666272).

The spelling of 1322350134041 in words is "one trillion, three hundred twenty-two billion, three hundred fifty million, one hundred thirty-four thousand, forty-one".