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13224023412555 = 353128438760027
BaseRepresentation
bin1100000001101111010100…
…1101111100111101001011
31201211012111221002000110110
43000123311031330331023
53213130244443200210
644043011003445403
72533255425240144
oct300336515747513
951735457060413
1013224023412555
11423930551535a
121596aa2826863
1374c0350b03b7
1433a0908b8acb
1517dec1bc4420
hexc06f537cf4b

13224023412555 has 16 divisors (see below), whose sum is σ = 21840967701504. Its totient is φ = 6825302406240.

The previous prime is 13224023412539. The next prime is 13224023412619. The reversal of 13224023412555 is 55521432042231.

It is not a de Polignac number, because 13224023412555 - 24 = 13224023412539 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14219379549 + ... + 14219380478.

It is an arithmetic number, because the mean of its divisors is an integer number (1365060481344).

Almost surely, 213224023412555 is an apocalyptic number.

13224023412555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13224023412555 is a deficient number, since it is larger than the sum of its proper divisors (8616944288949).

13224023412555 is a wasteful number, since it uses less digits than its factorization.

13224023412555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28438760066.

The product of its (nonzero) digits is 288000, while the sum is 39.

Adding to 13224023412555 its reverse (55521432042231), we get a palindrome (68745455454786).

The spelling of 13224023412555 in words is "thirteen trillion, two hundred twenty-four billion, twenty-three million, four hundred twelve thousand, five hundred fifty-five".

Divisors: 1 3 5 15 31 93 155 465 28438760027 85316280081 142193800135 426581400405 881601560837 2644804682511 4408007804185 13224023412555