Base | Representation |
---|---|
bin | 11000101000011011… |
… | …11111100010011011 |
3 | 1021010121111121112021 |
4 | 30110031333202123 |
5 | 204040333124311 |
6 | 10024114355311 |
7 | 645464055121 |
oct | 142415774233 |
9 | 37117447467 |
10 | 13224114331 |
11 | 567673890a |
12 | 269088bb37 |
13 | 132995002c |
14 | 8d6427911 |
15 | 525e71171 |
hex | 31437f89b |
13224114331 has 2 divisors, whose sum is σ = 13224114332. Its totient is φ = 13224114330.
The previous prime is 13224114257. The next prime is 13224114341. The reversal of 13224114331 is 13341142231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13224114331 - 217 = 13223983259 is a prime.
It is a super-2 number, since 2×132241143312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13224114296 and 13224114305.
It is not a weakly prime, because it can be changed into another prime (13224114341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612057165 + 6612057166.
It is an arithmetic number, because the mean of its divisors is an integer number (6612057166).
Almost surely, 213224114331 is an apocalyptic number.
13224114331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13224114331 is an equidigital number, since it uses as much as digits as its factorization.
13224114331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 25.
Adding to 13224114331 its reverse (13341142231), we get a palindrome (26565256562).
The spelling of 13224114331 in words is "thirteen billion, two hundred twenty-four million, one hundred fourteen thousand, three hundred thirty-one".
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