Base | Representation |
---|---|
bin | 10011001111100101111… |
… | …110001010111100111011 |
3 | 11200102101020211000120201 |
4 | 103033211332022330323 |
5 | 133131300242140443 |
6 | 2451301441103031 |
7 | 164353430034643 |
oct | 23174576127473 |
9 | 4612336730521 |
10 | 1322413240123 |
11 | 46a917887238 |
12 | 194361627a77 |
13 | 9791a7452c1 |
14 | 48010179523 |
15 | 245eb98034d |
hex | 133e5f8af3b |
1322413240123 has 2 divisors, whose sum is σ = 1322413240124. Its totient is φ = 1322413240122.
The previous prime is 1322413240081. The next prime is 1322413240157. The reversal of 1322413240123 is 3210423142231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1322413240123 - 29 = 1322413239611 is a prime.
It is a super-2 number, since 2×13224132401232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1322413240091 and 1322413240100.
It is not a weakly prime, because it can be changed into another prime (1322413240163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661206620061 + 661206620062.
It is an arithmetic number, because the mean of its divisors is an integer number (661206620062).
Almost surely, 21322413240123 is an apocalyptic number.
1322413240123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322413240123 is an equidigital number, since it uses as much as digits as its factorization.
1322413240123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1322413240123 its reverse (3210423142231), we get a palindrome (4532836382354).
The spelling of 1322413240123 in words is "one trillion, three hundred twenty-two billion, four hundred thirteen million, two hundred forty thousand, one hundred twenty-three".
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