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13224133433 = 71889161919
BaseRepresentation
bin11000101000011100…
…00100001100111001
31021010121112120201202
430110032010030321
5204040334232213
610024115023545
7645464164610
oct142416041471
937117476652
1013224133433
1156767511a5
12269089abb5
131329958934
148d6430877
15525e76b58
hex314384339

13224133433 has 4 divisors (see below), whose sum is σ = 15113295360. Its totient is φ = 11334971508.

The previous prime is 13224133423. The next prime is 13224133499. The reversal of 13224133433 is 33433142231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13224133433 - 216 = 13224067897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13224133396 and 13224133405.

It is not an unprimeable number, because it can be changed into a prime (13224133423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 944580953 + ... + 944580966.

It is an arithmetic number, because the mean of its divisors is an integer number (3778323840).

Almost surely, 213224133433 is an apocalyptic number.

It is an amenable number.

13224133433 is a deficient number, since it is larger than the sum of its proper divisors (1889161927).

13224133433 is an equidigital number, since it uses as much as digits as its factorization.

13224133433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1889161926.

The product of its digits is 15552, while the sum is 29.

Adding to 13224133433 its reverse (33433142231), we get a palindrome (46657275664).

The spelling of 13224133433 in words is "thirteen billion, two hundred twenty-four million, one hundred thirty-three thousand, four hundred thirty-three".

Divisors: 1 7 1889161919 13224133433