Base | Representation |
---|---|
bin | 11110000100100010110100… |
… | …000101111010000000101011 |
3 | 122100021022210120102001102001 |
4 | 132010202310011322000223 |
5 | 114313320441013110033 |
6 | 1145140253505351431 |
7 | 36600003563230462 |
oct | 3604426405720053 |
9 | 570238716361361 |
10 | 132253654425643 |
11 | 3915a507094343 |
12 | 129bb789338577 |
13 | 58a460a03317a |
14 | 249317a9399d9 |
15 | 104534b102e7d |
hex | 7848b417a02b |
132253654425643 has 2 divisors, whose sum is σ = 132253654425644. Its totient is φ = 132253654425642.
The previous prime is 132253654425619. The next prime is 132253654425661. The reversal of 132253654425643 is 346524456352231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132253654425643 - 217 = 132253654294571 is a prime.
It is not a weakly prime, because it can be changed into another prime (132253654425143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66126827212821 + 66126827212822.
It is an arithmetic number, because the mean of its divisors is an integer number (66126827212822).
Almost surely, 2132253654425643 is an apocalyptic number.
132253654425643 is a deficient number, since it is larger than the sum of its proper divisors (1).
132253654425643 is an equidigital number, since it uses as much as digits as its factorization.
132253654425643 is an evil number, because the sum of its binary digits is even.
The product of its digits is 62208000, while the sum is 55.
The spelling of 132253654425643 in words is "one hundred thirty-two trillion, two hundred fifty-three billion, six hundred fifty-four million, four hundred twenty-five thousand, six hundred forty-three".
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