Search a number
-
+
132254021646233 is a prime number
BaseRepresentation
bin11110000100100011001001…
…111110101111011110011001
3122100021100202011101210100122
4132010203021332233132121
5114313322214020134413
61145140354144243025
736600015642446444
oct3604431176573631
9570240664353318
10132254021646233
113915a685400633
12129bb870310475
1358a4668138666
1424931b360a65b
15104536d48e108
hex7848c9faf799

132254021646233 has 2 divisors, whose sum is σ = 132254021646234. Its totient is φ = 132254021646232.

The previous prime is 132254021646167. The next prime is 132254021646259. The reversal of 132254021646233 is 332646120452231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129970214600704 + 2283807045529 = 11400448^2 + 1511227^2 .

It is a cyclic number.

It is not a de Polignac number, because 132254021646233 - 236 = 132185302169497 is a prime.

It is a super-2 number, since 2×1322540216462332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132254021646133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66127010823116 + 66127010823117.

It is an arithmetic number, because the mean of its divisors is an integer number (66127010823117).

Almost surely, 2132254021646233 is an apocalyptic number.

It is an amenable number.

132254021646233 is a deficient number, since it is larger than the sum of its proper divisors (1).

132254021646233 is an equidigital number, since it uses as much as digits as its factorization.

132254021646233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1244160, while the sum is 44.

The spelling of 132254021646233 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, twenty-one million, six hundred forty-six thousand, two hundred thirty-three".