Base | Representation |
---|---|
bin | 11110000100111110010110… |
… | …100010110011000011111011 |
3 | 122100101011010021202022202111 |
4 | 132010332112202303003323 |
5 | 114314312020201011242 |
6 | 1145202023544313151 |
7 | 36602101410641206 |
oct | 3604762642630373 |
9 | 570334107668674 |
10 | 132283223453947 |
11 | 39171000028a15 |
12 | 12a0545ba727b7 |
13 | 58a7340031617 |
14 | 2494783a3a93d |
15 | 1045ecbe9b817 |
hex | 784f968b30fb |
132283223453947 has 2 divisors, whose sum is σ = 132283223453948. Its totient is φ = 132283223453946.
The previous prime is 132283223453911. The next prime is 132283223453971. The reversal of 132283223453947 is 749354322382231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132283223453947 - 231 = 132281075970299 is a prime.
It is a super-3 number, since 3×1322832234539473 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132283223453891 and 132283223453900.
It is not a weakly prime, because it can be changed into another prime (132283223457947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66141611726973 + 66141611726974.
It is an arithmetic number, because the mean of its divisors is an integer number (66141611726974).
Almost surely, 2132283223453947 is an apocalyptic number.
132283223453947 is a deficient number, since it is larger than the sum of its proper divisors (1).
132283223453947 is an equidigital number, since it uses as much as digits as its factorization.
132283223453947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 52254720, while the sum is 58.
The spelling of 132283223453947 in words is "one hundred thirty-two trillion, two hundred eighty-three billion, two hundred twenty-three million, four hundred fifty-three thousand, nine hundred forty-seven".
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