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132283223453947 is a prime number
BaseRepresentation
bin11110000100111110010110…
…100010110011000011111011
3122100101011010021202022202111
4132010332112202303003323
5114314312020201011242
61145202023544313151
736602101410641206
oct3604762642630373
9570334107668674
10132283223453947
1139171000028a15
1212a0545ba727b7
1358a7340031617
142494783a3a93d
151045ecbe9b817
hex784f968b30fb

132283223453947 has 2 divisors, whose sum is σ = 132283223453948. Its totient is φ = 132283223453946.

The previous prime is 132283223453911. The next prime is 132283223453971. The reversal of 132283223453947 is 749354322382231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132283223453947 - 231 = 132281075970299 is a prime.

It is a super-3 number, since 3×1322832234539473 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132283223453891 and 132283223453900.

It is not a weakly prime, because it can be changed into another prime (132283223457947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66141611726973 + 66141611726974.

It is an arithmetic number, because the mean of its divisors is an integer number (66141611726974).

Almost surely, 2132283223453947 is an apocalyptic number.

132283223453947 is a deficient number, since it is larger than the sum of its proper divisors (1).

132283223453947 is an equidigital number, since it uses as much as digits as its factorization.

132283223453947 is an evil number, because the sum of its binary digits is even.

The product of its digits is 52254720, while the sum is 58.

The spelling of 132283223453947 in words is "one hundred thirty-two trillion, two hundred eighty-three billion, two hundred twenty-three million, four hundred fifty-three thousand, nine hundred forty-seven".