Base | Representation |
---|---|
bin | 11110000101001110011000… |
… | …001100011011000010110001 |
3 | 122100102210112111210211211001 |
4 | 132011032120030123002301 |
5 | 114320102240314341032 |
6 | 1145213551242122001 |
7 | 36603251004526042 |
oct | 3605163014330261 |
9 | 570383474724731 |
10 | 132300431012017 |
11 | 39178330271a94 |
12 | 12a088627b0301 |
13 | 58a8b53027248 |
14 | 24955371088c9 |
15 | 10466879c23e7 |
hex | 78539831b0b1 |
132300431012017 has 2 divisors, whose sum is σ = 132300431012018. Its totient is φ = 132300431012016.
The previous prime is 132300431011997. The next prime is 132300431012083. The reversal of 132300431012017 is 710210134003231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101905067798416 + 30395363213601 = 10094804^2 + 5513199^2 .
It is a cyclic number.
It is not a de Polignac number, because 132300431012017 - 235 = 132266071273649 is a prime.
It is not a weakly prime, because it can be changed into another prime (132300431012417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66150215506008 + 66150215506009.
It is an arithmetic number, because the mean of its divisors is an integer number (66150215506009).
Almost surely, 2132300431012017 is an apocalyptic number.
It is an amenable number.
132300431012017 is a deficient number, since it is larger than the sum of its proper divisors (1).
132300431012017 is an equidigital number, since it uses as much as digits as its factorization.
132300431012017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 132300431012017 its reverse (710210134003231), we get a palindrome (842510565015248).
The spelling of 132300431012017 in words is "one hundred thirty-two trillion, three hundred billion, four hundred thirty-one million, twelve thousand, seventeen".
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