Base | Representation |
---|---|
bin | 111101100110111000… |
… | …0101100001101000011 |
3 | 110122111021212212001001 |
4 | 1323031300230031003 |
5 | 4131423041042011 |
6 | 140440035552431 |
7 | 12362354620036 |
oct | 1731560541503 |
9 | 418437785031 |
10 | 132301112131 |
11 | 5112158a7a1 |
12 | 2178345b717 |
13 | c625848c46 |
14 | 6590d4701d |
15 | 3694da47c1 |
hex | 1ecdc2c343 |
132301112131 has 2 divisors, whose sum is σ = 132301112132. Its totient is φ = 132301112130.
The previous prime is 132301112071. The next prime is 132301112183. The reversal of 132301112131 is 131211103231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132301112131 - 215 = 132301079363 is a prime.
It is a super-2 number, since 2×1323011121312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132301112099 and 132301112108.
It is not a weakly prime, because it can be changed into another prime (132301112191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66150556065 + 66150556066.
It is an arithmetic number, because the mean of its divisors is an integer number (66150556066).
Almost surely, 2132301112131 is an apocalyptic number.
132301112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
132301112131 is an equidigital number, since it uses as much as digits as its factorization.
132301112131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 132301112131 its reverse (131211103231), we get a palindrome (263512215362).
The spelling of 132301112131 in words is "one hundred thirty-two billion, three hundred one million, one hundred twelve thousand, one hundred thirty-one".
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