13230113131 has 4 divisors (see below), whose sum is σ = 13261689000. Its totient is φ = 13198537264.

The previous prime is 13230113129. The next prime is 13230113159. The reversal of 13230113131 is 13131103231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131103231 = 14783 ⋅888257.

It is a cyclic number.

It is not a de Polignac number, because 13230113131 - 2¹ = 13230113129 is a prime.

It is a super-2 number, since 2×13230113131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13230113099 and 13230113108.

It is not an unprimeable number, because it can be changed into a prime (13230113191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15787306 + ... + 15788143.

It is an arithmetic number, because the mean of its divisors is an integer number (3315422250).

Almost surely, 2^13230113131 is an apocalyptic number.

13230113131 is a deficient number, since it is larger than the sum of its proper divisors (31575869).

13230113131 is an equidigital number, since it uses as much as digits as its factorization.

13230113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31575868.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13230113131 its reverse (13131103231), we get a palindrome (26361216362).

The spelling of 13230113131 in words is "thirteen billion, two hundred thirty million, one hundred thirteen thousand, one hundred thirty-one".