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132301404403 = 7241565313873
BaseRepresentation
bin111101100110111000…
…1110011100011110011
3110122111022102200221221
41323031301303203303
54131423124420103
6140440050125511
712362360245120
oct1731561634363
9418438380857
10132301404403
115112176a343
1221783580897
13c62591bc9c
146590dc1747
153694e111bd
hex1ecdc738f3

132301404403 has 16 divisors (see below), whose sum is σ = 151866801856. Its totient is φ = 112902543360.

The previous prime is 132301404383. The next prime is 132301404407. The reversal of 132301404403 is 304404103231.

It is a cyclic number.

It is not a de Polignac number, because 132301404403 - 229 = 131764533491 is a prime.

It is a super-2 number, since 2×1323014044032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (132301404407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9529675 + ... + 9543547.

It is an arithmetic number, because the mean of its divisors is an integer number (9491675116).

Almost surely, 2132301404403 is an apocalyptic number.

132301404403 is a deficient number, since it is larger than the sum of its proper divisors (19565397453).

132301404403 is a wasteful number, since it uses less digits than its factorization.

132301404403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19774.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 132301404403 its reverse (304404103231), we get a palindrome (436705507634).

The spelling of 132301404403 in words is "one hundred thirty-two billion, three hundred one million, four hundred four thousand, four hundred three".

Divisors: 1 7 241 1687 5653 13873 39571 97111 1362373 3343393 9536611 23403751 78424069 548968483 18900200629 132301404403