13230152330041 has 4 divisors (see below), whose sum is σ = 13230164744784. Its totient is φ = 13230139915300.

The previous prime is 13230152330039. The next prime is 13230152330071. The reversal of 13230152330041 is 14003325103231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13230152330041 - 2¹ = 13230152330039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13230152329991 and 13230152330009.

It is not an unprimeable number, because it can be changed into a prime (13230152330071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4441375 + ... + 6796036.

It is an arithmetic number, because the mean of its divisors is an integer number (3307541186196).

Almost surely, 2^{13230152330041} is an apocalyptic number.

It is an amenable number.

13230152330041 is a deficient number, since it is larger than the sum of its proper divisors (12414743).

13230152330041 is a wasteful number, since it uses less digits than its factorization.

13230152330041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12414742.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 13230152330041 its reverse (14003325103231), we get a palindrome (27233477433272).

The spelling of 13230152330041 in words is "thirteen trillion, two hundred thirty billion, one hundred fifty-two million, three hundred thirty thousand, forty-one".