Base | Representation |
---|---|
bin | 10011010000001010001… |
… | …101000001001101000011 |
3 | 11200110221121122010012210 |
4 | 103100022031001031003 |
5 | 133134021401042011 |
6 | 2451442033553203 |
7 | 164404460621355 |
oct | 23201215011503 |
9 | 4613847563183 |
10 | 1323021112131 |
11 | 4700a9a214a4 |
12 | 1944b1115803 |
13 | 979b6668c94 |
14 | 4806abb10d5 |
15 | 246350056a6 |
hex | 1340a341343 |
1323021112131 has 4 divisors (see below), whose sum is σ = 1764028149512. Its totient is φ = 882014074752.
The previous prime is 1323021112123. The next prime is 1323021112157. The reversal of 1323021112131 is 1312111203231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1323021112131 - 23 = 1323021112123 is a prime.
It is a super-2 number, since 2×13230211121312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1323021112098 and 1323021112107.
It is not an unprimeable number, because it can be changed into a prime (1323021113131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220503518686 + ... + 220503518691.
It is an arithmetic number, because the mean of its divisors is an integer number (441007037378).
Almost surely, 21323021112131 is an apocalyptic number.
1323021112131 is a deficient number, since it is larger than the sum of its proper divisors (441007037381).
1323021112131 is an equidigital number, since it uses as much as digits as its factorization.
1323021112131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 441007037380.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1323021112131 its reverse (1312111203231), we get a palindrome (2635132315362).
The spelling of 1323021112131 in words is "one trillion, three hundred twenty-three billion, twenty-one million, one hundred twelve thousand, one hundred thirty-one".
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