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132302143283161 is a prime number
BaseRepresentation
bin11110000101001111111110…
…010000001101111111011001
3122100102221221211202020020211
4132011033332100031333121
5114320114242140030121
61145214433210051121
736603341305560145
oct3605177620157731
9570387854666224
10132302143283161
1139179029856705
1212a09060119aa1
1358a90669ac037
14249565a6a6225
151046737e9bce1
hex7853fe40dfd9

132302143283161 has 2 divisors, whose sum is σ = 132302143283162. Its totient is φ = 132302143283160.

The previous prime is 132302143283053. The next prime is 132302143283171. The reversal of 132302143283161 is 161382341203231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124513104199936 + 7789039083225 = 11158544^2 + 2790885^2 .

It is a cyclic number.

It is not a de Polignac number, because 132302143283161 - 217 = 132302143152089 is a prime.

It is not a weakly prime, because it can be changed into another prime (132302143283171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151071641580 + 66151071641581.

It is an arithmetic number, because the mean of its divisors is an integer number (66151071641581).

Almost surely, 2132302143283161 is an apocalyptic number.

It is an amenable number.

132302143283161 is a deficient number, since it is larger than the sum of its proper divisors (1).

132302143283161 is an equidigital number, since it uses as much as digits as its factorization.

132302143283161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 40.

Adding to 132302143283161 its reverse (161382341203231), we get a palindrome (293684484486392).

The spelling of 132302143283161 in words is "one hundred thirty-two trillion, three hundred two billion, one hundred forty-three million, two hundred eighty-three thousand, one hundred sixty-one".