Base | Representation |
---|---|
bin | 11110000101001111111110… |
… | …010000001101111111011001 |
3 | 122100102221221211202020020211 |
4 | 132011033332100031333121 |
5 | 114320114242140030121 |
6 | 1145214433210051121 |
7 | 36603341305560145 |
oct | 3605177620157731 |
9 | 570387854666224 |
10 | 132302143283161 |
11 | 39179029856705 |
12 | 12a09060119aa1 |
13 | 58a90669ac037 |
14 | 249565a6a6225 |
15 | 1046737e9bce1 |
hex | 7853fe40dfd9 |
132302143283161 has 2 divisors, whose sum is σ = 132302143283162. Its totient is φ = 132302143283160.
The previous prime is 132302143283053. The next prime is 132302143283171. The reversal of 132302143283161 is 161382341203231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124513104199936 + 7789039083225 = 11158544^2 + 2790885^2 .
It is a cyclic number.
It is not a de Polignac number, because 132302143283161 - 217 = 132302143152089 is a prime.
It is not a weakly prime, because it can be changed into another prime (132302143283171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151071641580 + 66151071641581.
It is an arithmetic number, because the mean of its divisors is an integer number (66151071641581).
Almost surely, 2132302143283161 is an apocalyptic number.
It is an amenable number.
132302143283161 is a deficient number, since it is larger than the sum of its proper divisors (1).
132302143283161 is an equidigital number, since it uses as much as digits as its factorization.
132302143283161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 40.
Adding to 132302143283161 its reverse (161382341203231), we get a palindrome (293684484486392).
The spelling of 132302143283161 in words is "one hundred thirty-two trillion, three hundred two billion, one hundred forty-three million, two hundred eighty-three thousand, one hundred sixty-one".
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