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132303010011131 is a prime number
BaseRepresentation
bin11110000101010000110001…
…111010100001011111111011
3122100110001012020122120111202
4132011100301322201133323
5114320123031030324011
61145215055211044415
736603401631621641
oct3605206172413773
9570401166576452
10132303010011131
1139179434023213
1212a0926244070b
1358a917442631b
1424956dd841191
15104678910523b
hex785431ea17fb

132303010011131 has 2 divisors, whose sum is σ = 132303010011132. Its totient is φ = 132303010011130.

The previous prime is 132303010011041. The next prime is 132303010011157. The reversal of 132303010011131 is 131110010303231.

It is a strong prime.

It is an emirp because it is prime and its reverse (131110010303231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132303010011131 - 210 = 132303010010107 is a prime.

It is a super-2 number, since 2×1323030100111312 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (132303010011191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151505005565 + 66151505005566.

It is an arithmetic number, because the mean of its divisors is an integer number (66151505005566).

Almost surely, 2132303010011131 is an apocalyptic number.

132303010011131 is a deficient number, since it is larger than the sum of its proper divisors (1).

132303010011131 is an equidigital number, since it uses as much as digits as its factorization.

132303010011131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 132303010011131 its reverse (131110010303231), we get a palindrome (263413020314362).

The spelling of 132303010011131 in words is "one hundred thirty-two trillion, three hundred three billion, ten million, eleven thousand, one hundred thirty-one".