Search a number
-
+
1323031300993 is a prime number
BaseRepresentation
bin10011010000001010110…
…011111000101110000001
311200110222022210202201001
4103100022303320232001
5133134032003112433
62451443040212001
7164404643335453
oct23201263705601
94613868722631
101323031300993
11470104750546
121944b460a001
13979b87c57ac
144806c2a42d3
1524635d6957d
hex1340acf8b81

1323031300993 has 2 divisors, whose sum is σ = 1323031300994. Its totient is φ = 1323031300992.

The previous prime is 1323031300939. The next prime is 1323031301041. The reversal of 1323031300993 is 3990031303231.

Together with previous prime (1323031300939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 940294817344 + 382736483649 = 969688^2 + 618657^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323031300993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1323031300933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661515650496 + 661515650497.

It is an arithmetic number, because the mean of its divisors is an integer number (661515650497).

Almost surely, 21323031300993 is an apocalyptic number.

It is an amenable number.

1323031300993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323031300993 is an equidigital number, since it uses as much as digits as its factorization.

1323031300993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 39366, while the sum is 37.

The spelling of 1323031300993 in words is "one trillion, three hundred twenty-three billion, thirty-one million, three hundred thousand, nine hundred ninety-three".