Base | Representation |
---|---|
bin | 10011010000001010110… |
… | …111000011110110001001 |
3 | 11200110222101101001000011 |
4 | 103100022313003312021 |
5 | 133134032211224001 |
6 | 2451443110111521 |
7 | 164404653402235 |
oct | 23201267036611 |
9 | 4613871331004 |
10 | 1323032133001 |
11 | 470105169657 |
12 | 1944b494b5a1 |
13 | 979b8a273c7 |
14 | 4806c43d5c5 |
15 | 24635e80d51 |
hex | 1340adc3d89 |
1323032133001 has 2 divisors, whose sum is σ = 1323032133002. Its totient is φ = 1323032133000.
The previous prime is 1323032132963. The next prime is 1323032133011. The reversal of 1323032133001 is 1003312303231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1289360250000 + 33671883001 = 1135500^2 + 183499^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323032133001 - 219 = 1323031608713 is a prime.
It is not a weakly prime, because it can be changed into another prime (1323032133011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661516066500 + 661516066501.
It is an arithmetic number, because the mean of its divisors is an integer number (661516066501).
Almost surely, 21323032133001 is an apocalyptic number.
It is an amenable number.
1323032133001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323032133001 is an equidigital number, since it uses as much as digits as its factorization.
1323032133001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 1323032133001 its reverse (1003312303231), we get a palindrome (2326344436232).
The spelling of 1323032133001 in words is "one trillion, three hundred twenty-three billion, thirty-two million, one hundred thirty-three thousand, one".
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