Base | Representation |
---|---|
bin | 1100000010000110110100… |
… | …1011100100001100001011 |
3 | 1201211210210111221200021121 |
4 | 3000201231023210030023 |
5 | 3213231204220120133 |
6 | 44045532525420111 |
7 | 2533600636101304 |
oct | 300415513441413 |
9 | 51753714850247 |
10 | 13230331020043 |
11 | 4240a51a46205 |
12 | 159816310a637 |
13 | 74c7cbb0b817 |
14 | 33a4cc4bb7ab |
15 | 17e24082002d |
hex | c086d2e430b |
13230331020043 has 2 divisors, whose sum is σ = 13230331020044. Its totient is φ = 13230331020042.
The previous prime is 13230331020019. The next prime is 13230331020059. The reversal of 13230331020043 is 34002013303231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13230331020043 is a prime.
It is not a weakly prime, because it can be changed into another prime (13230331029043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615165510021 + 6615165510022.
It is an arithmetic number, because the mean of its divisors is an integer number (6615165510022).
Almost surely, 213230331020043 is an apocalyptic number.
13230331020043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13230331020043 is an equidigital number, since it uses as much as digits as its factorization.
13230331020043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 13230331020043 its reverse (34002013303231), we get a palindrome (47232344323274).
The spelling of 13230331020043 in words is "thirteen trillion, two hundred thirty billion, three hundred thirty-one million, twenty thousand, forty-three".
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