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1323055400153 is a prime number
BaseRepresentation
bin10011010000001100001…
…111110100010011011001
311200111001000011010112112
4103100030033310103121
5133134104140301103
62451445300522105
7164405355226424
oct23201417642331
94614030133475
101323055400153
11470117310603
121945006b0335
13979c07b2956
14480715789bb
1524638029cd8
hex1340c3f44d9

1323055400153 has 2 divisors, whose sum is σ = 1323055400154. Its totient is φ = 1323055400152.

The previous prime is 1323055400137. The next prime is 1323055400237. The reversal of 1323055400153 is 3510045503231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 669299063449 + 653756336704 = 818107^2 + 808552^2 .

It is an emirp because it is prime and its reverse (3510045503231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1323055400153 - 24 = 1323055400137 is a prime.

It is not a weakly prime, because it can be changed into another prime (1323055400123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661527700076 + 661527700077.

It is an arithmetic number, because the mean of its divisors is an integer number (661527700077).

Almost surely, 21323055400153 is an apocalyptic number.

It is an amenable number.

1323055400153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323055400153 is an equidigital number, since it uses as much as digits as its factorization.

1323055400153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 32.

The spelling of 1323055400153 in words is "one trillion, three hundred twenty-three billion, fifty-five million, four hundred thousand, one hundred fifty-three".