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1323068160497 is a prime number
BaseRepresentation
bin10011010000001101000…
…000011111100111110001
311200111001220011102102212
4103100031000133213301
5133134120422113442
62451450434221505
7164405601543536
oct23201500374761
94614056142385
101323068160497
11470123536646
12194504a24895
13979c332ca55
144807313ad8d
15246391eaa82
hex1340d01f9f1

1323068160497 has 2 divisors, whose sum is σ = 1323068160498. Its totient is φ = 1323068160496.

The previous prime is 1323068160481. The next prime is 1323068160503. The reversal of 1323068160497 is 7940618603231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 867498508816 + 455569651681 = 931396^2 + 674959^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323068160497 - 24 = 1323068160481 is a prime.

It is not a weakly prime, because it can be changed into another prime (1323068160397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661534080248 + 661534080249.

It is an arithmetic number, because the mean of its divisors is an integer number (661534080249).

Almost surely, 21323068160497 is an apocalyptic number.

It is an amenable number.

1323068160497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323068160497 is an equidigital number, since it uses as much as digits as its factorization.

1323068160497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 50.

The spelling of 1323068160497 in words is "one trillion, three hundred twenty-three billion, sixty-eight million, one hundred sixty thousand, four hundred ninety-seven".