Base | Representation |
---|---|
bin | 11110000101010111010010… |
… | …110010111001001010110011 |
3 | 122100110201020200021121110201 |
4 | 132011113102302321022303 |
5 | 114320231342023010003 |
6 | 1145222213214540031 |
7 | 36604040146522516 |
oct | 3605272262711263 |
9 | 570421220247421 |
10 | 132310004110003 |
11 | 391813a3007215 |
12 | 12a0a694807617 |
13 | 58a9a1a444275 |
14 | 2495ba46a2d7d |
15 | 1046a48155b1d |
hex | 7855d2cb92b3 |
132310004110003 has 2 divisors, whose sum is σ = 132310004110004. Its totient is φ = 132310004110002.
The previous prime is 132310004109989. The next prime is 132310004110013. The reversal of 132310004110003 is 300011400013231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132310004110003 - 25 = 132310004109971 is a prime.
It is not a weakly prime, because it can be changed into another prime (132310004110013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155002055001 + 66155002055002.
It is an arithmetic number, because the mean of its divisors is an integer number (66155002055002).
Almost surely, 2132310004110003 is an apocalyptic number.
132310004110003 is a deficient number, since it is larger than the sum of its proper divisors (1).
132310004110003 is an equidigital number, since it uses as much as digits as its factorization.
132310004110003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 132310004110003 its reverse (300011400013231), we get a palindrome (432321404123234).
The spelling of 132310004110003 in words is "one hundred thirty-two trillion, three hundred ten billion, four million, one hundred ten thousand, three".
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