Base | Representation |
---|---|
bin | 10011010000001110111… |
… | …010110101100111000011 |
3 | 11200111011010111211110011 |
4 | 103100032322311213003 |
5 | 133134202124412011 |
6 | 2451453541445351 |
7 | 164406441261046 |
oct | 23201672654703 |
9 | 4614133454404 |
10 | 1323100232131 |
11 | 47013a651527 |
12 | 194513710857 |
13 | 979c9b7b952 |
14 | 480774c8c5d |
15 | 2463be33621 |
hex | 1340eeb59c3 |
1323100232131 has 2 divisors, whose sum is σ = 1323100232132. Its totient is φ = 1323100232130.
The previous prime is 1323100232107. The next prime is 1323100232161. The reversal of 1323100232131 is 1312320013231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1323100232131 - 239 = 773344418243 is a prime.
It is a super-2 number, since 2×13231002321312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1323100232161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661550116065 + 661550116066.
It is an arithmetic number, because the mean of its divisors is an integer number (661550116066).
Almost surely, 21323100232131 is an apocalyptic number.
1323100232131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323100232131 is an equidigital number, since it uses as much as digits as its factorization.
1323100232131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1323100232131 its reverse (1312320013231), we get a palindrome (2635420245362).
The spelling of 1323100232131 in words is "one trillion, three hundred twenty-three billion, one hundred million, two hundred thirty-two thousand, one hundred thirty-one".
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