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13231013233147 is a prime number
BaseRepresentation
bin1100000010001001010111…
…0110000000000111111011
31201211212120001122200201121
43000202111312000013323
53213234103341430042
644050124335530111
72533623561601633
oct300422566000773
951755501580647
1013231013233147
114241272046a96
121598313689937
1374c8aa260c08
1433a554d456c3
1517e28067c367
hexc0895d801fb

13231013233147 has 2 divisors, whose sum is σ = 13231013233148. Its totient is φ = 13231013233146.

The previous prime is 13231013233129. The next prime is 13231013233169. The reversal of 13231013233147 is 74133231013231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13231013233147 - 231 = 13228865749499 is a prime.

It is a super-2 number, since 2×132310132331472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13231013233117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615506616573 + 6615506616574.

It is an arithmetic number, because the mean of its divisors is an integer number (6615506616574).

Almost surely, 213231013233147 is an apocalyptic number.

13231013233147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13231013233147 is an equidigital number, since it uses as much as digits as its factorization.

13231013233147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 34.

Adding to 13231013233147 its reverse (74133231013231), we get a palindrome (87364244246378).

The spelling of 13231013233147 in words is "thirteen trillion, two hundred thirty-one billion, thirteen million, two hundred thirty-three thousand, one hundred forty-seven".