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132310243120201 is a prime number
BaseRepresentation
bin11110000101010111100001…
…000010101001010001001001
3122100110201212100000120211021
4132011113201002221101021
5114320232334214321301
61145222253033432441
736604046111213326
oct3605274102512111
9570421770016737
10132310243120201
1139181505a14103
1212a0a74086b721
1358a9a57b09713
142495bc831bb4d
151046a5e1188a1
hex7855e10a9449

132310243120201 has 2 divisors, whose sum is σ = 132310243120202. Its totient is φ = 132310243120200.

The previous prime is 132310243120193. The next prime is 132310243120229. The reversal of 132310243120201 is 102021342013231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124587118659600 + 7723124460601 = 11161860^2 + 2779051^2 .

It is a cyclic number.

It is not a de Polignac number, because 132310243120201 - 23 = 132310243120193 is a prime.

It is not a weakly prime, because it can be changed into another prime (132310243120291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155121560100 + 66155121560101.

It is an arithmetic number, because the mean of its divisors is an integer number (66155121560101).

Almost surely, 2132310243120201 is an apocalyptic number.

It is an amenable number.

132310243120201 is a deficient number, since it is larger than the sum of its proper divisors (1).

132310243120201 is an equidigital number, since it uses as much as digits as its factorization.

132310243120201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 132310243120201 its reverse (102021342013231), we get a palindrome (234331585133432).

The spelling of 132310243120201 in words is "one hundred thirty-two trillion, three hundred ten billion, two hundred forty-three million, one hundred twenty thousand, two hundred one".