13231124340001 has 4 divisors (see below), whose sum is σ = 13248329964100. Its totient is φ = 13213918715904.

The previous prime is 13231124339947. The next prime is 13231124340023. The reversal of 13231124340001 is 10004342113231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9215328776976 + 4015795563025 = 3035676^2 + 2003945^2 .

It is a cyclic number.

It is not a de Polignac number, because 13231124340001 - 2¹¹ = 13231124337953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13231124340061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8602810896 + ... + 8602812433.

It is an arithmetic number, because the mean of its divisors is an integer number (3312082491025).

Almost surely, 2^{13231124340001} is an apocalyptic number.

It is an amenable number.

13231124340001 is a deficient number, since it is larger than the sum of its proper divisors (17205624099).

13231124340001 is an equidigital number, since it uses as much as digits as its factorization.

13231124340001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17205624098.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13231124340001 its reverse (10004342113231), we get a palindrome (23235466453232).

The spelling of 13231124340001 in words is "thirteen trillion, two hundred thirty-one billion, one hundred twenty-four million, three hundred forty thousand, one".