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1323120202123 is a prime number
BaseRepresentation
bin10011010000010000000…
…111000001000110001011
311200111012112002102010111
4103100100013001012023
5133134222232431443
62451455533455151
7164410103103436
oct23202007010613
94614175072114
101323120202123
1147014a951255
1219451a3414b7
1397a01051505
144807a00681d
152463da7a69d
hex134101c118b

1323120202123 has 2 divisors, whose sum is σ = 1323120202124. Its totient is φ = 1323120202122.

The previous prime is 1323120202099. The next prime is 1323120202171. The reversal of 1323120202123 is 3212020213231.

It is a weak prime.

It is an emirp because it is prime and its reverse (3212020213231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1323120202123 - 217 = 1323120071051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1323120202094 and 1323120202103.

It is not a weakly prime, because it can be changed into another prime (1323120202823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661560101061 + 661560101062.

It is an arithmetic number, because the mean of its divisors is an integer number (661560101062).

Almost surely, 21323120202123 is an apocalyptic number.

1323120202123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323120202123 is an equidigital number, since it uses as much as digits as its factorization.

1323120202123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 1323120202123 its reverse (3212020213231), we get a palindrome (4535140415354).

The spelling of 1323120202123 in words is "one trillion, three hundred twenty-three billion, one hundred twenty million, two hundred two thousand, one hundred twenty-three".