Base | Representation |
---|---|
bin | 11000101001010011… |
… | …11101010110100011 |
3 | 1021011010022001212202 |
4 | 30110221331112203 |
5 | 204044222223121 |
6 | 10024535443415 |
7 | 645613300412 |
oct | 142451752643 |
9 | 37133261782 |
10 | 13231445411 |
11 | 567a895858 |
12 | 269322656b |
13 | 132b318b52 |
14 | 8d73b5479 |
15 | 52691d40b |
hex | 314a7d5a3 |
13231445411 has 2 divisors, whose sum is σ = 13231445412. Its totient is φ = 13231445410.
The previous prime is 13231445407. The next prime is 13231445417. The reversal of 13231445411 is 11454413231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13231445411 - 22 = 13231445407 is a prime.
It is a super-3 number, since 3×132314454113 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13231445417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615722705 + 6615722706.
It is an arithmetic number, because the mean of its divisors is an integer number (6615722706).
Almost surely, 213231445411 is an apocalyptic number.
13231445411 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231445411 is an equidigital number, since it uses as much as digits as its factorization.
13231445411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5760, while the sum is 29.
Adding to 13231445411 its reverse (11454413231), we get a palindrome (24685858642).
The spelling of 13231445411 in words is "thirteen billion, two hundred thirty-one million, four hundred forty-five thousand, four hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •