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132315345130354 = 266157672565177
BaseRepresentation
bin11110000101011100010001…
…001001010001001101110010
3122100111020000220100120000021
4132011130101021101031302
5114320323311323132404
61145224455211314054
736604316412454441
oct3605342111211562
9570436026316007
10132315345130354
1139183693965921
1212a0b72544b92a
1358aa38bb33a39
14249614db74d58
151046c5bec0454
hex785711251372

132315345130354 has 4 divisors (see below), whose sum is σ = 198473017695534. Its totient is φ = 66157672565176.

The previous prime is 132315345130291. The next prime is 132315345130357. The reversal of 132315345130354 is 453031543513231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 112795976097025 + 19519369033329 = 10620545^2 + 4418073^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 132315345130354.

It is not an unprimeable number, because it can be changed into a prime (132315345130357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33078836282587 + ... + 33078836282590.

Almost surely, 2132315345130354 is an apocalyptic number.

132315345130354 is a deficient number, since it is larger than the sum of its proper divisors (66157672565180).

132315345130354 is an equidigital number, since it uses as much as digits as its factorization.

132315345130354 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66157672565179.

The product of its (nonzero) digits is 972000, while the sum is 43.

Adding to 132315345130354 its reverse (453031543513231), we get a palindrome (585346888643585).

The spelling of 132315345130354 in words is "one hundred thirty-two trillion, three hundred fifteen billion, three hundred forty-five million, one hundred thirty thousand, three hundred fifty-four".

Divisors: 1 2 66157672565177 132315345130354