Base | Representation |
---|---|
bin | 11000101001011000… |
… | …00100010000000001 |
3 | 1021011011100010211021 |
4 | 30110230010100001 |
5 | 204044342413303 |
6 | 10024555345441 |
7 | 645621061336 |
oct | 142454042001 |
9 | 37134303737 |
10 | 13231997953 |
11 | 56801329a9 |
12 | 2693452281 |
13 | 132b4804b5 |
14 | 8d74ba98d |
15 | 5269cbebd |
hex | 314b04401 |
13231997953 has 2 divisors, whose sum is σ = 13231997954. Its totient is φ = 13231997952.
The previous prime is 13231997921. The next prime is 13231997959. The reversal of 13231997953 is 35979913231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7011047824 + 6220950129 = 83732^2 + 78873^2 .
It is a cyclic number.
It is not a de Polignac number, because 13231997953 - 25 = 13231997921 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13231997953.
It is not a weakly prime, because it can be changed into another prime (13231997959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615998976 + 6615998977.
It is an arithmetic number, because the mean of its divisors is an integer number (6615998977).
Almost surely, 213231997953 is an apocalyptic number.
It is an amenable number.
13231997953 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231997953 is an equidigital number, since it uses as much as digits as its factorization.
13231997953 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1377810, while the sum is 52.
The spelling of 13231997953 in words is "thirteen billion, two hundred thirty-one million, nine hundred ninety-seven thousand, nine hundred fifty-three".
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