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1323203121433 is a prime number
BaseRepresentation
bin10011010000010101000…
…011010101000100011001
311200111102022010011001001
4103100111003111010121
5133134404444341213
62451512055025001
7164412130645624
oct23202503250431
94614368104031
101323203121433
11470192736806
1219454206b161
1397a152945ab
144808702cdbb
1524645ea91dd
hex134150d5119

1323203121433 has 2 divisors, whose sum is σ = 1323203121434. Its totient is φ = 1323203121432.

The previous prime is 1323203121353. The next prime is 1323203121503. The reversal of 1323203121433 is 3341213023231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1178325447049 + 144877674384 = 1085507^2 + 380628^2 .

It is a cyclic number.

It is not a de Polignac number, because 1323203121433 - 213 = 1323203113241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1323203121533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661601560716 + 661601560717.

It is an arithmetic number, because the mean of its divisors is an integer number (661601560717).

Almost surely, 21323203121433 is an apocalyptic number.

It is an amenable number.

1323203121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323203121433 is an equidigital number, since it uses as much as digits as its factorization.

1323203121433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 1323203121433 its reverse (3341213023231), we get a palindrome (4664416144664).

The spelling of 1323203121433 in words is "one trillion, three hundred twenty-three billion, two hundred three million, one hundred twenty-one thousand, four hundred thirty-three".