132320400212131 has 4 divisors (see below), whose sum is σ = 132534164995000. Its totient is φ = 132106635429264.

The previous prime is 132320400212129. The next prime is 132320400212137. The reversal of 132320400212131 is 131212004023231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132320400212131 - 2¹ = 132320400212129 is a prime.

It is a super-2 number, since 2×132320400212131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132320400212096 and 132320400212105.

It is not an unprimeable number, because it can be changed into a prime (132320400212137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106882390506 + ... + 106882391743.

It is an arithmetic number, because the mean of its divisors is an integer number (33133541248750).

Almost surely, 2^{132320400212131} is an apocalyptic number.

132320400212131 is a deficient number, since it is larger than the sum of its proper divisors (213764782869).

132320400212131 is an equidigital number, since it uses as much as digits as its factorization.

132320400212131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 213764782868.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 132320400212131 its reverse (131212004023231), we get a palindrome (263532404235362).

The spelling of 132320400212131 in words is "one hundred thirty-two trillion, three hundred twenty billion, four hundred million, two hundred twelve thousand, one hundred thirty-one".