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132321122181433 is a prime number
BaseRepresentation
bin11110000101100001101001…
…011110111110000100111001
3122100111202221111220011021001
4132011201221132332010321
5114320422124234301213
61145231252341445001
736604612521545113
oct3605415136760471
9570452844804231
10132321122181433
11391860889598a9
1212a10878110761
1358aaa9c96ba63
14249653b10a3b3
151046e992691dd
hex7858697be139

132321122181433 has 2 divisors, whose sum is σ = 132321122181434. Its totient is φ = 132321122181432.

The previous prime is 132321122181427. The next prime is 132321122181527. The reversal of 132321122181433 is 334181221123231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118502557548544 + 13818564632889 = 10885888^2 + 3717333^2 .

It is a cyclic number.

It is not a de Polignac number, because 132321122181433 - 25 = 132321122181401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132321122181392 and 132321122181401.

It is not a weakly prime, because it can be changed into another prime (132321122181403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160561090716 + 66160561090717.

It is an arithmetic number, because the mean of its divisors is an integer number (66160561090717).

Almost surely, 2132321122181433 is an apocalyptic number.

It is an amenable number.

132321122181433 is a deficient number, since it is larger than the sum of its proper divisors (1).

132321122181433 is an equidigital number, since it uses as much as digits as its factorization.

132321122181433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 37.

The spelling of 132321122181433 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, one hundred twenty-two million, one hundred eighty-one thousand, four hundred thirty-three".