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13232113201009 is a prime number
BaseRepresentation
bin1100000010001101011101…
…1010000010111101110001
31201211222101201102211222001
43000203113122002331301
53213243331434413014
644050425432014001
72533663046302213
oct300432732027561
951758351384861
1013232113201009
114241786a3a13a
12159857bb31301
1374ca24100081
1433a61b0765b3
1517e2e7008974
hexc08d7682f71

13232113201009 has 2 divisors, whose sum is σ = 13232113201010. Its totient is φ = 13232113201008.

The previous prime is 13232113200991. The next prime is 13232113201019. The reversal of 13232113201009 is 90010231123231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11606947168609 + 1625166032400 = 3406897^2 + 1274820^2 .

It is an emirp because it is prime and its reverse (90010231123231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13232113201009 - 217 = 13232113069937 is a prime.

It is not a weakly prime, because it can be changed into another prime (13232113201019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616056600504 + 6616056600505.

It is an arithmetic number, because the mean of its divisors is an integer number (6616056600505).

Almost surely, 213232113201009 is an apocalyptic number.

It is an amenable number.

13232113201009 is a deficient number, since it is larger than the sum of its proper divisors (1).

13232113201009 is an equidigital number, since it uses as much as digits as its factorization.

13232113201009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 28.

The spelling of 13232113201009 in words is "thirteen trillion, two hundred thirty-two billion, one hundred thirteen million, two hundred one thousand, nine".