Base | Representation |
---|---|
bin | 10011010000010101101… |
… | …001100000110101101001 |
3 | 11200111102222221200201221 |
4 | 103100111221200311221 |
5 | 133134420030143423 |
6 | 2451513053342041 |
7 | 164412312015436 |
oct | 23202551406551 |
9 | 4614388850657 |
10 | 1323213131113 |
11 | 470198353175 |
12 | 194545497921 |
13 | 97a1738a693 |
14 | 480884b6b8d |
15 | 24646cd4e5d |
hex | 13415a60d69 |
1323213131113 has 2 divisors, whose sum is σ = 1323213131114. Its totient is φ = 1323213131112.
The previous prime is 1323213131099. The next prime is 1323213131117. The reversal of 1323213131113 is 3111313123231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1206640734784 + 116572396329 = 1098472^2 + 341427^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323213131113 - 213 = 1323213122921 is a prime.
It is not a weakly prime, because it can be changed into another prime (1323213131117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661606565556 + 661606565557.
It is an arithmetic number, because the mean of its divisors is an integer number (661606565557).
Almost surely, 21323213131113 is an apocalyptic number.
It is an amenable number.
1323213131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323213131113 is an equidigital number, since it uses as much as digits as its factorization.
1323213131113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 972, while the sum is 25.
Adding to 1323213131113 its reverse (3111313123231), we get a palindrome (4434526254344).
The spelling of 1323213131113 in words is "one trillion, three hundred twenty-three billion, two hundred thirteen million, one hundred thirty-one thousand, one hundred thirteen".
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