Base | Representation |
---|---|
bin | 111101100111011110… |
… | …1110010100001101001 |
3 | 110122112200220200021221 |
4 | 1323032331302201221 |
5 | 4131443224314423 |
6 | 140442041102041 |
7 | 12363021455140 |
oct | 1731675624151 |
9 | 418480820257 |
10 | 132321323113 |
11 | 51131a34591 |
12 | 2178a187921 |
13 | c629aa43c5 |
14 | 65938c8757 |
15 | 3696a47e5d |
hex | 1ecef72869 |
132321323113 has 4 divisors (see below), whose sum is σ = 151224369280. Its totient is φ = 113418276948.
The previous prime is 132321323111. The next prime is 132321323129. The reversal of 132321323113 is 311323123231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311323123231 = 113 ⋅2755071887.
It is a cyclic number.
It is not a de Polignac number, because 132321323113 - 21 = 132321323111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132321323111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9451523073 + ... + 9451523086.
It is an arithmetic number, because the mean of its divisors is an integer number (37806092320).
Almost surely, 2132321323113 is an apocalyptic number.
It is an amenable number.
132321323113 is a deficient number, since it is larger than the sum of its proper divisors (18903046167).
132321323113 is an equidigital number, since it uses as much as digits as its factorization.
132321323113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18903046166.
The product of its digits is 1944, while the sum is 25.
Adding to 132321323113 its reverse (311323123231), we get a palindrome (443644446344).
The spelling of 132321323113 in words is "one hundred thirty-two billion, three hundred twenty-one million, three hundred twenty-three thousand, one hundred thirteen".
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